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Distribution law of mathematical answers in college entrance examination
Let me answer you. The answer options of multiple-choice questions in college entrance examination are different according to the specific situation. Let's just say, on the whole. Average distribution. Why? Because the teacher who wrote the paper found a situation, that is, if there are ten A's and the other five, and I don't know anything, I will get all A's, and you will find that you are better than those students who can get them. In order to prevent this from happening, the teacher who writes the paper stipulates that it can only be distributed equally. If it's 20, each person has 5.

But I want to bless you, don't believe this too much. It depends on your own ability. I have studied this before. But you get an average score on this basis, and you always doubt that you are wrong. Then you changed. But most of the changes are wrong. Although you also have five options, there are many mistakes.

And sometimes the options are not five, but four, six, five, five or three, seven, five, five (less) or four, six, four, six and so on.

This method can only check. Estimate your own right and wrong. Instead of changing your answer according to him.

That's all.

Please tell me if you have any good application methods. The above is my experience.