Ms. Wang's favorite products are sold at the same price in two shopping malls, A and B, and the two shopping malls adopt different promotion methods. Shopping in the mall for more than 100 yuan at one time, and 20% off the excess; Shopping in Mall B exceeds 50 yuan at one time, with a 10% discount for the excess. So how much more than B mall?

Solution: If Ms. Wang spends more than X yuan in shopping mall A, it will be more favorable than shopping mall B.

(X- 100)×80%+ 100 < 50+(X-50)×90%

0.8X-80+ 100 150

2. In the zoo, two baboons are playing on the seesaw. The big baboon weighing 33 kilograms threw the little baboon into the sky, which made the little baboon scream. At this time, the little monkey, whose weight is only half that of the little monkey, jumped on the little monkey from the tree, only to see the big monkey leave the ground and be thrown up. Do you know how much this little monkey weighs?

Solution: let the weight of the little monkey be X kg,

33≤X+2X

33≤3X

X≥ 1 1

So X≥ 1 1kg.

3. A group plans to make a batch of "Chinese knots". If everyone does five, it will be nine more than planned. If everyone does four, it will be less than planned 15. How many team members are there? How many Chinese knots do they plan to make?

There are x members in the team.

5x=4x+ 15+9

5x-4x= 15+9

4. A middle school organizes a spring outing for junior one students. It was originally planned to rent a number of 45-seat buses, but 15 people had no seats. If you rent the same number of 60-seat buses and have one more, the rest will be just full. We want to ask

(1) What is the number of students in Grade One? How many 45-seat buses were originally planned to be rented?

Solution: Rent 45-seat bus X and 60-seat bus (x- 1).

45x+ 15=60(x- 1)

Solution: x=5 45x+ 15=240 (person)

The number of students in Grade One is 240.

It is planned to rent five 45-seat buses.

5. Input a batch of accounting statements into the computer. It takes 20 hours for Party A to do it alone, and it takes 12h for Party B to do it alone. Now Party A works alone for 4 hours, and the rest is done by both parties. How long will both parties cooperate?

Solutions; Set to XH

1/5+ 1/20X+ 1/ 12X = 1

8/60X=4/5

X=6

The cooperation time of A and B is 6H.

The sum of 6 A, B and C is 53, so the ratio of A to B is 4: 3, C is 2 less than B, B is () and C is ().

Let a be 4X. Then b is 3X. C is 3X-2.

4X+3X+3X-2=53

10X=53+2

10X=55

X=5.5

3X= 16.5

3X-2= 16.5-2= 14.5

B is 16.5 and c is 14.5.

The length of thick candle is the same as that of thin candle. The thick candle burns for 5 hours and the thin candle burns for 4 hours. After the power failure, two candles are lit at the same time, and they are extinguished at the same time after the call. It turns out that the length of a thick candle is four times that of a thin candle. How long is the power outage?

Set the power outage for x hours. The thick candle burns 1/5 per hour, and the thin candle burns 1/4 per hour.

1- 1/5X = 4( 1- 1/4)

1- 1/5X=4-X

- 1/5+X=4- 1

4/5X=3

X= 15/4

8. For a three-digit number, the number of the hundredth digit is greater than the number of the tenth digit 1, and the number of the tenth digit is three times smaller than 2. If the order of the three digits is reversed, the sum of the three digits and the original three digits is 1 17 1. Find these three numbers.

Let ten digits be x.

Then100× (x+1)+10x+3x-2+100 * (x+1)+/kloc-0+.

simplify

424x= 1272

So: x=3

This three-digit number is 437.

Class 3, Grade 1, Senior High School donated books to Hope Primary School. A class library 152 volumes. The number of books donated by class two is the average of three classes, and the number of books donated by class three is 40% of the total number of books donated by grade three. How many books did Class Three donate?

Solution: Set up 2 classes to donate X copies.

3x= 152+x+3xX40%

3x= 152+x+6/5x

3x-x-6/5x= 152

4/5x= 152

X = 190...(2) Class

190X3=570 (Ben)

10. It is known that it takes 12 days for both parties to complete a job at the same time. If Party A and Party B complete this work alone, the number of days required by Party B is 65438+ 0.5 times that required by Party A. How many days will it take for Party A and Party B to complete the work alone?

Let a be x days, then b is 1.5x,

1/x+ 1/ 1.5x = 1/ 12，

Process, both sides are multiplied by x to get1+11.5 = x/12, and x=20.

1 1. If Team A contracts a project within the specified date, Team B will need more than 3 days to complete it. As a result, Team A and Team B cooperated for two days, and the rest was done by Team B alone, just on the specified date. How many days is the specified date?

Suppose the date is x days.

The working efficiency of A is 1/x, and that of B is 1/(x+3).

Then the equation is, (1/x+1(x+3)) * 2+(x-2)/(x+3) =1,

Process, 2/x+2/(x+3)+(x-2)/(x+3) =1.

x/(x+3)=(x-2)/x

x=6

12 each worker in a workshop can produce 12 bolts or 18 nuts, and each bolt should be equipped with two nuts. There are currently 28 workers. How to allocate the number of workers so that the daily output just matches?

Solution: Assuming that X individuals are designated to produce bolts, then (28-x) individuals produce nuts.

Because each bolt should have two nuts, the number of bolts is twice as much as the number of nuts.

2× 12x= 18(28-x)

X= 12, so 28-x=28- 12= 16.

That is, 12 people should be allocated to produce bolts and 16 people to produce nuts.

13 A and B trains run in opposite directions. The speed of the train is 60 kilometers per hour, and the length is 150 meters. Train B has a speed of 75 kilometers per hour and a length of 120 meters. How long does it take for two cars to meet from front to back?

It can be assumed that train A is stationary, so the speed of train B relative to train A is 60+75 =135 km/h; The two cars went from the front to the rear 150+ 120=270 meters =0.27 kilometers.

Then the required time t=0.27/ 135=0.002 hours.

14 The price of a commodity is now reduced 10%. In order to keep the sales amount unchanged, what percentage will the sales volume increase over the original price?

Assumption: increase by x%

90%*( 1+x%)= 1

Solution: x = 1/9

Therefore, the sales volume increased by11.11%compared with the original price.

15 The sum of the original unit prices of the two commodities A and B is 100 yuan. Due to market changes, a commodity has decreased by 10%. B After the price adjustment of the commodity is 5%, the sum of the unit prices of the two commodities has increased by 2%. What are the original unit prices of A and B respectively?

If the original unit price of commodity A is X yuan, then B is100-X.

( 1- 10%)X+( 1+5%)( 100-X)= 100( 1+2%)

The result x = one in X=20 yuan.

100-20=80 B

16. The number of people in Workshop A is 30 less than 4/5 of Workshop B. If 10 is transferred from Workshop B to Workshop A, then the number of people in Workshop A is 3/4 of Workshop B. Find the original number of people in each workshop.

There are x people in Workshop B. According to the equality of the total number, the equation is listed as follows:

X+4/5X-30 = X- 10+3/4(X- 10)

X=250

So the number of people in Workshop A is 250*4/5-30= 170.

Description:

The left side of the equation is adjusted first, and the right side of the equation is adjusted later.

17 A rides a bike from place A to place B, and B rides a bike from place B to place A, both of which advance at the same speed. You should know that they set off at 8 o'clock in the morning at the same time. By morning 10, they are still 36 kilometers apart. At noon 12, they are 36 kilometers apart. How to find the distance between a and b? (Equation)

Let the distance between a and b be x.

x-(x/4)=x-72

x=288

Answer: The distance between A and B is 288.

18. both a car and b car are 180 meters long. If two trains travel relatively, it takes *** 12 seconds from the front to the rear; If driving in the same direction, it takes 60 seconds from the front of car A to the rear of car B, and the speed remains unchanged. Find the speed of a car and b car.

The sum of the speeds of the two vehicles is [180 * 2]/12 = 30m/s.

Let the speed of a be x, then the speed of b is 30-X.

180*2=60[X-(30-X)]

X= 18

That is, the speed of car A is 18m/s and the speed of car B is12m/s..

19. Two candles of the same length, the thick one can burn for 3 hours and the thin one can burn for 8/3 hours. Light two candles at the same time when there is a power failure, and blow them out when a phone comes in. The thick one is twice as long as the thin one. Find the time of power failure.

Suppose the blackout time is X.

Let the total length be 1, then the coarse firing is 1/3 and the fine firing is 3/8.

1-X/3=2[ 1-3X/8]

X=2.4

That's a power outage of 2.4 hours.

A factory produced 2300 machines this year, which was 25% higher in the first half and 15% lower in the second half. How many machines were produced in the second half of this year?

Solution: If X production units are set in the second half of the year, [2300-X] units will be produced in the first half of the year.

According to the meaning of the question:1-15% x+1+25% 2300-x = 2300.

Solution: 93 1

A: 93 1 set will be produced in the second half of the year.

2 1 A rides a bike from a place to b place, and b rides a bike from b place to a place. Both of them are driving at high speed, so we can know that they set off at 8 am at the same time. By morning 10, the difference between them is still 36 kilometers, and by noon 12, the difference between them is 36 kilometers. How to find the distance between a and b? ]

Let the distance between a and b be x.

x-(x/4)=x-72

x=288

A: The distance between A and B is 288 meters.

1-X/3=2[ 1-3X/8]

X=2.4

That's a power outage of 2.4 hours.

20. A factory produced 2300 machines this year, which was 25% higher than last year in the first half and 15% lower than last year in the second half. How many machines were produced in the second half of this year?

Solution: If X production units are set in the second half of the year, [2300-X] units will be produced in the first half of the year.

2 1 Xiao Ming and Xiao Cong buy grain at the same store. Xiaoming buys 100 kg each time, and Xiaocong spends 100 yuan each time. But the unit price of these two kinds of grain is different. If it is stipulated that the average unit price of grain purchased twice is low, then this way of purchasing grain is cost-effective. Then can you judge who is more cost-effective, Xiao Ming or Xiao Cong?

One:

(1) The cooperation efficiency of Team A and Team B is 1/6, that of Team B and Team C is1/0, and that of Team A and Team C is (2/3)÷5=2/ 15.

Therefore, the cooperation efficiency of the three teams is (1/6+110+2/15) ÷ 2 =1/5.

It takes1÷ (1/5-110) =10 days for Team A to complete all the projects alone.

It takes team B1÷ (1/5-2/15) =15 days to complete all the projects alone.

It takes1÷ (1/5-1/6) for Group C to complete all the projects alone = 30 days.

(2) The daily wages of Party A and Party B are 8700/6= 1450 yuan, 9500/ 10=950 yuan, and 5500/5 =100 yuan.

Therefore, the daily wages of Party A, Party B and Party C are (1450+950+10/00) ÷ 2 =1750 yuan.

So Party A's daily wage 1750-950=800 yuan, Party B's daily wage1750-1/kloc-0 = 650 yuan, and Party C's daily wage 1750- 1450=300 yuan.

Therefore, it takes 10 days for Team A to complete all the projects alone, and the cost is 800×10 = 8,000 yuan.

It takes 15 days for Team B to complete all the projects alone, and the cost is 650× 15=9750 yuan.

It takes 30 days for Team C to complete the whole project alone, and the cost is 300×30=9000 yuan.

Therefore, if the time limit for a project does not exceed 15 days to complete all the projects, Team A will spend the least money to complete this project alone.

Or (1) the number of days that three teams completed alone.

Answer: 2 ÷ (1/6+2/3 ÷ 5-110) =10 days,

B:1÷ (1/6-110) =15 days,

C:1÷ (110-115) = 30 days.

(2) First of all, Team C could not be completed within 15 days, so Team C was excluded.

Daily wages of every two teams and:

A and C 8700 ÷ 6 = 1450 yuan; Ethylene propylene 9500 ÷ 10 = 950 yuan; A and C 5500 ÷ 5 = 1 100 yuan.

Personal daily wages of Party A and Party B:

Team A: (1100+1450-950) ÷ 2 = 800 yuan; Team b: 1450-800 = 650 yuan.

Because 800× 10 < 650× 15, the cost of finding a team is the least.

Two. Solution: Let's assume that the number of workers recruiting Class A jobs is X, the number of workers recruiting Class B jobs is NX (n = 2), and the monthly salary of the recruited workers is Y yuan.

Then y = 600x+ 1000nx.

Because with the increase of the number of B-type jobs, when the number of B-type jobs is twice that of A-type jobs (n = 2), the monthly salary is the least. Therefore, the minimum monthly salary can be achieved by recruiting 50 people for the first-class position and 100 people for the first-class position, and the minimum salary is130,000 yuan.

Three: 1008 > 100× 9 = 900 yuan.

13 14÷9= 1 12

Solution: there are x people in group A and 1 12-x people in group B.

1 1x+ 13( 1 12-x)= 13 14

1 1x+ 1456- 13x = 13 14

-2x+ 1456 = 13 14

-2x=- 142

x=7 1

112-x =112-71= 41(person)

A: 7 1 person for tour group a and 4 1 person for tour group b. ..

Four:

Let the number of passengers added per minute be x.

(a+30x)/30=(a+ 10x)/20

D: x=a/30

The number of ticket takers per minute at each ticket gate is: a/ 15.

The required number of ticket gates is [a+5 * (a/15)]/[(a/15) * 5] = 4. It's up to you whether to add or not reward points.

A new building has been built in a certain unit, and water pipes need to be laid from the main water pipe at 132 meters. At present, there are 8 meters and 5 meters of water pipes to choose from. Please design the scheme, how to choose these two kinds of water pipes, so as to just lay them from the main pipeline to this building? How many kinds of such schemes are there? If each 8-meter-long water pipe is 50 yuan and each 5-meter-long water pipe is 35 yuan, which scheme is the most economical?

Solution: set 8 m water pipe x and 5 m water pipe y.

8x+5y= 132

Solution:

x=4 y=20

x=9 y= 12

x= 14 y=4

From the meaning of the question, because we want to save the most money, we should save the most money when there are 14 8-meter long water pipes and 4 5-meter long water pipes.

23 known equations ax+by=c

a'x+b'y=c '

His solution is x=3.

y=4

Find the solution of equation 3ax+2by=5c.

3a'+2b'y=5c '

3ax+2by=5c

3a'+2b'y=5c' both expressions are divided by 5.

Get 3/5ax+2/5by = c.

3/5a'x+2/5b'y=c '

Let x=3.

Y=4 is brought into the original equation respectively.

3/5xa+2/5yb=c

3a + 4b=c

3/5ya'+2/5yb'=c '

3a' + 4b'=c '

Because the results are the same, the letters are the same, so are the coefficients.

3/5x=3 x=5 2/5y=4 y= 10

In order to stimulate domestic demand, Shandong Province launched the activity of "Home Appliances Going to the Countryside". A home appliance enterprise sold 960 type I and type II refrigerators to farmers one month before the activity, and the number of type I and type II refrigerators sold to farmers in the first month after the activity increased by 30% and 25% respectively compared with the month before the activity. The sales volume of these two models is 1228 units.

(1) How many refrigerators were sold to farmers one month before the activity?

(2) If the price of type I refrigerator is 2298 yuan, the price of type II refrigerator is 1999 yuan. According to the policy of "home appliances going to the countryside", the government subsidizes farmers who buy refrigerators according to 13% of the price of each refrigerator. In the first month after the activity, the government subsidized 1228 first-and second-class refrigerators sold to farmers. How much was it? (The result retains two significant figures)

& lt 1 & gt； , solutions; Suppose the first refrigerator X is sold one month before the activity, then the second model is sold.

Then continuous; X times

x=560

Answer; One month before the activity, 560 type I refrigerators were sold to farmers, and 960-560=400 type II refrigerators were sold to farmers.

& lt2> According to the meaning of the question, first calculate the sales volume of two kinds of refrigerators in the first month after they start their activities.

Sales of Type I refrigerators in the first month after the activity: 560x( 1+30%)=728 units.

Farmers' subsidy for a type of refrigerator is: 728 X.

Sales of Type II refrigerators in the first month after the activity: 400 x

The farmer's subsidy for type II refrigerator is: 500 x.

How much did the government * * * subsidize: 2174852.72+129935 = 2304787.72 Keep two valid figures as 2300000.

In order to meet the public's demand for quality education, a middle school decided to change the conditions of running a school and planned to demolish some old school buildings and build new ones. Demolition of old school buildings per square meter of 80 yuan, new school buildings per square meter of 700 yuan. It is planned to demolish 7200 square meters of old school buildings during the year. In order to expand the green area, only 80% of the newly-built school buildings were completed, while more than 10% of the school buildings were demolished. As a result, the total planned demolition area has just been completed. 1. What is the original planned demolition construction area of square meters? 2. If 200 yuan is needed for greening 1 m2, how many m2 can the remaining funds in the demolition construction project actually be used for greening?

Solution: If X square meters are demolished and Y square meters are built, there is an equation:

x+y=7200.............( 1)

1. 1x+0.8y=7200.......(2)

(2) 0.1x-0.2y = 0 in-(1), so x=2y, 3y=7200 in (1).

∴y=2400m？ ，x=7200-2400=4800m？

That is, the original planned demolition of 4800m? The new 2400m? .

The original planned capital is 4800×80+2400×700=2064000 yuan =2064000 yuan.

The actual funds used are1.1× 4800× 80+0.8× 2400× 700 = 1766400 yuan =1766400 yuan.

Deposit 2064000- 1766400=297600 yuan.

So the green area is 297,600/200 =1488m?

A middle school has a four-story teaching building with eight classrooms on each floor. There are four doors into the building, two of which are as big as the main entrance, and the two side doors are as big. During the security check, four doors were tested: when one main entrance and two side doors were opened at the same time, 560 students could pass in 2 minutes; When a main entrance and a side door are opened at the same time, 800 students can pass in 4 minutes. 1. How many students can pass through a main entrance and a side door every minute on average? 2. During the inspection, it was found that the efficiency of going out was reduced by 20% due to the crowded students in an emergency. According to the safety inspection, students in the whole building have to pass through these four doors within 5 minutes in case of emergency. Suppose that each classroom in this teaching building has a maximum of 45 students. Q: Are these four doors in line with the regulations? Please provide a justification for the answer.

On average, there is a main entrance and a side door that can pass X and Y students every minute.

Then (X+2Y)*2=560.

(X+Y)*4=800

Get the door Y=80 and the door X= 120.

the second question

The total number of people in the building is 4*8*45= 1440.

The number of people who can pass through four doors in 5 minutes = (2x+2y) * 5 * (1-20%) =1600.

So it is qualified.

Ms. Wang's favorite products are sold at the same price in two shopping malls, A and B, and the two shopping malls adopt different promotion methods. One-time shopping in a shopping mall exceeds 100 yuan, and the excess part is 20% off; Shopping in Mall B exceeds 50 yuan at one time, with a 10% discount for the excess. So how much more than B mall?

Solution: If Ms. Wang spends more than X yuan in shopping mall A, it will be more favorable than shopping mall B.

(X- 100)×80%+ 100 < 50+(X-50)×90%

0.8X-80+ 100 150

In the zoo, two baboons are playing on the seesaw. The big baboon weighing 33kg lifted the little baboon into the sky, making the little baboon scream. At this time, the little monkey, whose weight is only half that of the little monkey, jumped on the little monkey from the tree, only to see the big monkey leave the ground and be lifted up. Do you know how much this little monkey weighs?

Solution: let the weight of the little monkey be X kg,

33≤X+2X

33≤3X

X≥ 1 1

So X≥ 1 1kg.

29. It takes 15 days for Party A to complete a project alone, and 12 days for Party B to complete a project alone. Now that Party A and Party B have cooperated for three days, Party A has other tasks, and the remaining projects will be completed by Party B alone. How many days does it take Party B to complete all the projects?

The analysis assumes that the total project amount is 1, and the equivalent relationship is: a completed workload +B completed workload = total workload.

Solution: Assume that it takes X days for B to complete all projects, and the total workload is 1. From the meaning of the question, (115+12) × 3+x12 =1,solve this equation, 65438.

12+15+5x = 605x = 33 ∴ x = 335 = 635a: omitted.

30. The distance between Station A and bilibili is 480 kilometers. The local train departs from Station A at a speed of 90km per hour, and the express train departs from bilibili at a speed of140km per hour.

(1) The local train starts first 1 hour, and the express train starts again. The two cars are driving in opposite directions. How many hours after the express train leaves, will the two cars meet?

(2) After two cars started at the same time and walked in opposite directions for several hours, the two cars were 600 kilometers apart?

(3) Two cars start at the same time, and the local train runs in the same direction behind the express train. How many hours later, the distance between the express train and the local train is 600 kilometers?

(4) Two cars leave in the same direction at the same time, and the express train is behind the local train. How many hours will the express catch up with the local train?

(5) After the local train 1 hour, the two cars are driving in the same direction, and the express train is behind the local train. How many hours after the express train leaves, will it catch up with the local train?

The key to this problem is to understand the meaning of opposite direction, opposite direction and same direction, and to understand the driving process. So it can be combined with graphic analysis.

(1) parsing: When encountering a problem, draw it as:

The equivalent relationship is: distance traveled by local train+distance traveled by express train = 480km.

Solution: Suppose that two cars meet after the express train leaves X hours. From the meaning of the title, 140x+90(x+ 1)=480.

To solve this equation, 230x = 390 ∴ x =11623a: abbreviated.

Analysis: run in reverse, and the drawing is expressed as:

The equivalent relationship is: distance traveled by two cars +480 km =600 km.

Solution: Let the distance between two cars be 600 kilometers after X hours. Judging from the meaning of the question, (140+90)x+480=600 solves this equation, and 230x= 120 ∴ x= 1223.

(3) Analysis: The equivalent relationship is: the distance traveled by the express train-the distance traveled by the local train +480km = 600km.

Solution: Suppose the distance between two cars is 600 kilometers after X hours. According to the meaning of the question, (140-90) x+480 = 600 50x =120 ∴ x = 2.4 A: omitted.

Analysis: Trace back the problem and draw it as follows:

The equivalent relationship is: express distance = local distance+480km.

Solution: Set the express train to catch up with the local train after X hours. From the meaning of the question, 140x=90x+480 can solve this equation, and 50x=480∴ x=9.6 A: abbreviated.

Analysis: Tracing back to the source, the equivalent relationship is: express distance = local distance +480 km.

Solution: Set the express train to catch up with the local train after X hours. From the meaning of the title,140 x = 90 (x+1)+48050x = 570, and x= 1 1.4.

3 1 A store increased the purchase price of a certain garment by 40%, then marked it and sold it at a 20% discount. As a result, each piece of clothing still earned 15 yuan. What is the purchase price of each piece of clothing?

Analysis: It is the key to explore the implied conditions in the topic, and the cost can be directly set to X yuan.

Purchase discount rate, bid price, preferential price and profit

Twenty percent off (1+40%) X twenty percent off (1+40%) X 15.

Equivalence relationship: (profit = discount price-purchase price) discount price-purchase price = 15.

Solution: Let the purchase price be X yuan, 80% X (1+40%)-X = 15, X= 125 A: omitted.

32. A classmate deposited 250 yuan in the bank for half a year. After half a year, * * * got the principal and interest and 252.7 yuan. What is the annual interest rate of the bank for half a year? (excluding interest tax)

Analysis: equivalence relation: sum of principal and interest = principal ×( 1+ interest rate) Solution: Let the actual interest rate for half a year be x, 250( 1+x)=252.7, and x=0.0 108.

So the annual interest rate is 0.0 108×2=0.02 16.

33. Two people, A and B, walk in opposite directions from A and B, which are 30 kilometers apart. Three hours later, they were three kilometers apart. After 2 hours, the distance from A to B is twice as long as that from B to A. Find the speed of A and B. 。

Analysis: Let the velocities of A and B be x km/h and y km/h respectively. In the first case, A and B are still 3 km apart before they meet.

In the second case, A and B are 3 kilometers apart after meeting.

A: The speeds of A and B are 4 km/h and 5 km/h respectively; Or the speeds of a and b are km/h and km/h respectively.

Pants can be matched, tops can be produced at 360m, pants can be matched at 240m, and * * * can produce 240 sets. 4. A shopping mall sells an electrical appliance at a fixed price, and each one can make a profit in 48 yuan. Selling six electrical appliances at a 10% discount on the fixed price is equal to the profit of selling nine electrical appliances in 30 yuan. What is the purchase price and fixed price of each electrical appliance? 4. Solution: Assume that the purchase price of each electrical appliance is X yuan and the price is Y yuan. Answer: The purchase price of each electrical appliance is 162 yuan, and the price is 2 10 yuan. Solution: 10% discount is sold at 90% price, and profit = price-purchase price. 5. Solution: Suppose xm3 wood is used as the desktop, ym3. 4m3 of wood can make a square table with 300 square tables. 5. A square table consists of 65,438+0 desktops and 4 legs. If 1 m3 wood can be used to make 50 desktops or 300 legs of a square table, and there is 100 m3 wood, how many cubic meters of wood can be used to make desktops and legs? How many square tables can you make? 5. Assume that xm3 wood is used as a table top and ym3 wood is used as a table leg. 2) 6× 50 = 300 (sheets). Answer: 6m3 wood is used as the table top and 4m3 wood is used as the table legs, which just makes a square table and can make 300 square tables. 6. Party A and Party B arrive from Party A and Party B at 8 am. 12, 36km apart. Knowing that A walks 2km more than B every hour, we can find the distance between A and B. If A and B are xkm apart and B walks ykm every hour, then A walks (y+2) km7. A middle school organizes students to have a spring outing. It was originally planned to rent a number of 45-seat buses, but 15 people had no seats. If you rent the same number of 60 buses, there will be one more bus, and the rest of the buses are just full. It is understood that the daily rent of 45 buses is 220 yuan, and the daily rent of 60 buses is 300 yuan. Q: 1) How many students are there in the spring outing? How many 45-seat buses were originally planned to rent? (2) If you rent a similar car and want everyone to have a seat, how to rent a car is more cost-effective?