Since bd is perpendicular to ce and intersects O, the area of quadrilateral CDBE is1/2 * BD * CE =1/2 * 3 * 8 =12.

Because the area of triangle ADE accounts for 1/4 of triangle ABC (because BD and CE are the median lines of AC and AB respectively, the height and bottom of triangle ADE are 1/2 of triangle ABC).

Therefore, the area of quadrangle CDCE accounts for 3/4 of triangle ABC.

The area of triangle ABC is 16.