∫M, n is the midpoint of CC 1 and BC.
∴ MN//BC 1
Also: BC1/ad1
∴ MN//AD 1
The angle between Mn and CD 1 is equal to the angle between AD 1 and CD 1.
AC= AD 1=AC in △AD 1C。
The out-of-plane straight line CD 1 forms an angle of 60 with MN.