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A math problem of Peking University's independent enrollment
Let tgx = t and cotx =1/t.

Tanx+ root 3 = a

Cotx+ root 3 = b

A and b are rational numbers.

(A root 3)(b root 3) = t * 1/t = 1

Ab+3-(a+b)* Root 3 = 1

(a+b) * Root 3 = 2+ab

A+b is a rational number, 2+ab is also a rational number, and the root number 3 is an irrational number.

If you want the above formula to hold, only a+b = 0.

Then ab = -2

And such a and b are not rational numbers and contradictions.

So there is no x.