So ∠ Abe+∠ CDE = 360-110 = 250.

Because the bisector of ∠ABE and ∠CDE intersects at point F.

So ∠ ABF+∠ CDF = 125, ∠ FBE+∠ FDE = 125.

The sum of the four internal angles of a quadrilateral is 360.

So ∠ f = 360-∠ FBE-∠ FDE-∠ E.

= 360-(∠FBE+∠FDE)- 1 10

=360 - 125 - 1 10

= 125