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Who knows the 28th problem of mathematics in Taiyuan, Shanxi in 2006?
Let AO=R CO=r angle AOB = n.

S yin =S fan aob-S fan cod=(n pie) /360-(n pie R2)/360.

=[n Pai (R+r)(R-r)]/360

= 1/2*[(n pie R)/ 180-(n pie r)/ 180]*d

= 1/2(l 1+l2)*d

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