y=xe^x

hello

=x'e^x+xe^x

=( 1+x)e^x

=0

x=- 1

x & lt- 1，y '

When x=- 1, y'=0, y takes the minimum value-1/e;

X>- 1, y'>0, y monotonically increases.

PS:

Attached figure y = xe x