1. congruence, with side lengths of 3 and 5 respectively and equal included angle (SAS).

2。 If the speed is different, the CQ on the other side should be =5, then point P should be at the midpoint of BC, so BP=PC=4.

So the time is 4/3 seconds, and the speed of Q point should be 5 divided by 4/3, which is 15/4.

3。 3X+8= 15/4*X, not +20, wrong direction. x=32/3

3X=32=28+4 is the midpoint of BC.