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Mathematics examination paper for junior high school entrance examination
If the score of the solution (1) is 50, the question 10 must be done correctly. Among the other three questions, the correct answer probability of 1 question is 1 2, 1 question is 1 3, and 1 question is 13.

So the probability of getting 50 points is: p =12? 1 3 ? 1 4 = 1 24 .

(2) According to the meaning of the question, the score range of this candidate is {35, 40, 45, 50}.

35 points means that only 7 questions are done correctly, and the rest are done wrong.

So the probability is p1=12? 2 3 ? 3 4 = 6 24 = 1 4 ,

The probability of getting 40 points is: p 2 =12? 2 3 ? 3 4 + 1 2 ? 1 3 ? 3 4 + 1 2 ? 2 3 ? 1 4 = 1 1 24 .

Similarly, the probability of getting 45 points is: p 3 = 6 24.

The probability of getting 50 points is: p 4 = 1 24.

So the distribution list with a score of ξ is:

ξ 35 40 45 50 p14124 624124 Mathematical expectation e ξ = 35×14+40×124+45× 624+.