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Fourth grade Book 2 Unit 3 math diary
This morning, we had an interesting Olympiad math class. Teacher Ding came in with a big smile on her face.

The classroom suddenly became quiet. The teacher said to us, "I'll give you a question first: two integers."

The quotient of division is

12

, the rest is

26

The sum of dividend, divisor and quotient remainder is equal to

454

What is the divisor?

I read it again, two ". When I got the question, I thought: What is the bonus of this question?

How to find the divisor? But recalling that teachers often say that drawing line segments is a magic weapon to solve application problems. Why don't I try?

What about trying? So I began to draw: first, take the divisor as a multiple, and the dividend is several times more than the divisor.

26

Draw quotient and remainder again. Oh, it turned out to be a matter of doubling. The formula is: (

454

12

26

26

)÷(

12+ 1

)

=390÷

13=30

I think: we have learned to use it.

x

The method of calculation. I'll write out the formula of the text first. Divider × quotient

+

remainder

+

divisor

+

business

+

remainder

=454

Then set the divisor to

X

The formula is: x×12+26+x+12+26 = 454.

I will put it first.

12

and

26

After subtraction, the dividend and divisor are left, and then because there is a remainder in the dividend.

I'll lose it again

26

So the dividend is equal to

12

. The divisor is

30

. Expressed by formula, it is:

X× 12+26+X+26+ 12 = 454