According to Newton's second law: Bqv=mv2R, the solution is: r = mvbq.
Maximum distance of particles on OM: 2r = 2mvbq.
(2) Make the trajectory diagram of ions emitted in the +y direction from emission to the third crossing of the MN boundary, as shown in Figure 2. The moving time in the magnetic field is t 1 = t = 2π meq.
Time of moving in electric field: T2 = 2va = 2mvqem = 2mvqe.
t=t 1+t2=2πmqB+2mvqE
(3) The radius of the particle's circular motion in the magnetic field: r = mvqb. All these ions should pass through OM at a speed equal to the +x direction, and the shape of the magnetic field is shown by the solid line in Figure 3.
From the geometric relationship: S=S big -S small.
Is it big? =2( 13πR2？ 12R2sin 120)
S small = 2 (16 π R2? 12R2sin60)
S=2( 13πR2？ 12R2sin 120)？ 2( 16πR2？ 12r 2 sin 60)= 13πR2 =π3(mvqB)2 =πm2 v 23 B2 Q2
Answer: (1) The maximum distance for ions to hit OM is 2mvBq；;
(2) It takes 2πmqB+ for the ions emitted in the+y direction to pass through the MN boundary for the third time. What is your evaluation of this answer? Put away comments//high quality or satisfaction or special types or recommended answers dottimewindow.iperformance & window.iperformance.mark ('c _ best',+newdate); Lawyer recommendation service: If your problem has not been solved, please describe your problem in detail and consult other similar problems free of charge through Baidu Law Pro 20 19-08-20. When a particle moves along the X axis, the relationship between its acceleration A and position coordinate X is a = 2+6x? (SI), if the initial velocity of the particle at the origin is 03220 18-03-08, the relationship between acceleration a and position coordinate x is a = 2+6x 2, and the coordinate of the point closest to the origin is _ _ _ _ _ _ _ _ _ _ _ and the relationship between acceleration a and position coordinate x is a = 2+6x 2. The origin speed is 062017-08-14 ∫∫∫ x2y2zdxdy, where ∫ is 752065433, the coordinate origin is the center of the circle, and r is the radius. As shown in the figure, in the plane rectangular coordinate system xoy, the coordinates of point A on the Y axis are (0,3), and the coordinates of point B on the X axis are (10,0) 32016-05-19 (2014? As shown in the figure, in the plane rectangular coordinate system, point O is the coordinate origin, and the straight line y=-x+n intersects the X axis and Y axis at two points B and C respectively. Motion equation of a particle in xOy plane142019-12-18. Find more questions like t = 1s and t = 2s4? & gt recommended for you: F.context('cmsRight', [{'URL':'/d01373f082025aaf511aa256e9edab64034f1a07? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId':'A24KA00562 '，}，{ ' URL ':/s？ word = % E6 % AC % A7 % E6 % B4 % B2 % E6 % 9D % AF & sa = searchpromo _ ozb _ zhidao _ tuijian '，' src ':'/3 BF 33 a 87 e 950352 AAF 5 df 4954 143 fbf2b 2 1 18 b6b？ x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId ':' '，}])； The price of electric cars has dropped many times. Is the quality guaranteed? What impact will the "network toilet" have? Is Huaqiang North's second-hand mobile phone reliable? Why is the cost of cancer treatment getting higher and higher? I recommend f.context ('recbrand', [{"img": "\/86D6277F9E2F07083523F69DFB 24B 899A901F20d? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto "，" url":"/hm.js？ 6859 ce 5a af 00 FB 00387 e 6434 E4 FCC 925 "； var s = document . getelementsbytagname(" script ")[0]； s.parentNode.insertBefore(hm，s)； })(); window . TT = 1720 109570；