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The eighth grade, the second volume of geometric mathematics problems.
(1) Because AB is perpendicular to BC and DE is perpendicular to BC, AB is parallel to FD.

So angle CAE= angle AEF,

Because AE equals EA, ce equals af, and angle CAE= equals angle AEF,

So triangle ACE and triangle EAF are equal triangles,

So AC=EF and AC//EF, so ACEF is a parallelogram.

(2)ACEF can't be square.

Because if ACEF is a square, the angle ACE is equal to 90 degrees, and the angle ACB is equal to 90 degrees, then point E is on the straight line CB and point D is on the straight line CB, then DE can't vertically divide BC? So the quadrilateral ACEF can't be a square.