2' s m+ 1 power (m+1) = 2× 2m 2 can be written as 2 times 2m power.
Raise the common factor twice
[5^(m+ 1)]×[2^m]-[5^m]×[2^(m+ 1]
=[5×5^m]×[2^m]-[5^m]×[2×2^m]
=5×5^m×2^m-2×5^m×2^m
=5^m×2^m(5-2)
=3×5^m×2^m
So the answer of m = 2 supplements the 30th power of 2,1-0.25, 14.
Because 1/-0.25 =-4.
So the original question becomes (-4)14× 230 = 414× 230 = 228× 230 = 258, and the answer to the 58th power of result 2 is added. 3. Classmate, I don't know how many times your question 256 is.
From 2× 5 = 10, 2× 5 2 =10 2, … please calculate how many digits the integer 256× 625 10 has.
Because 256 = 2 to the eighth power and 625 = 5 to the fourth power.
therefore
625 10 = 5 to the 40th power.
According to the meaning of the question, if 2 and 5 are combined, it can be written as the power of 10, how many digits are there, plus the previous digits.