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Elective course 1- 1 mathematical derivative formula
C'=0

(x^m)'=mx^(m- 1)

(a^x)'=a^x*lna

(e^x)'=e^x

[log(a,x)]'= 1/(xlna)

(lnx)'= 1/x

(sinx)'=cosx

(cosx)'=sinx

[f(x)+g(x)]'=f'(x)+g'(x)

[C*f(x)]'=C*f'(x)

[f(x)* g(x)]' = f '(x)g(x)+f(x)* g '(x)

[f(x)/g(x)]=[f '(x)g(x)-f(x)g '(x)]/g? (10)