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The problem of eighth grade mathematics competition
Solution: 6. The original formula = [2 (x+3)-12-(x-1) (x-3)]/2 (x 2-9) = (2x+6-12-x65438+.

=-(x^2-6x+9)/2(x^2-9)=-(x-3)/(2x+6)

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4. Original formula = 3sqrt (2)-6sqrt (5)-3sqrt (2) =-6sqrt (5)

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19. the original formula = a2-(B2-6b+9) = a2-(b-3) 2 = [a+(b-3)] [a-(b-3)] = (a+b-3) (a-b+).

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18. The original formula = (4x) 2-(x2+4) 2 = [4x+(x2+4)] =-(x+2) 2 (x-2) 2.

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17. The original formula = x2+3x+2+1/4 = x2+3x+9/2 = (x+3/2) 2.

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3. The original formula =4-3+3sqrt(3)-3=3sqrt(3)-2.

Note: a B- stands for the b power of a.

Sqrt(x) stands for root number X.