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Mathematical running
Let the tiger take a step, and the rabbit can run 1 1 According to the seven-step distance of the tiger, so the rabbit takes a step, and the distance is 7a/1.

Let the time for a tiger to take one step be b, and the rabbit can run four steps according to the time for a tiger to run three steps, so the time for a rabbit to take one step is 3b/4.

It can be concluded that the speed of the tiger is a/b.

The rabbit's speed is (7a/ 1 1)/(3b/4), which is 28a/33b.

Let the tiger catch up with the rabbit at t.

Then finally, the distance between the tiger and the rabbit is 50.

The expression is: (a/b)*t-(28a/33b)*t=50.

Simplify and get (5/33)*(a/b)*t=50.

It is known that the speed of the tiger is a/b, and the time for the tiger to chase the rabbit is t.

Then (a/b)*t is how many meters the tiger ran and caught up with the rabbit.

Available from (111) * (a/b) * t = 50.

(a/b) * t = 330m

So the tiger has to run 330 meters to catch up with the rabbit.