(2) Let the gravity of a hook code be G and the length of a cell on the lever be L, then according to the equilibrium condition, we can know that 4G×3L=nG×2L.
The solution is n=6 (pieces), so six identical hook codes should be hung at B;
(3) "Force× distance from fulcrum to force point = resistance× distance from fulcrum to resistance point" is obtained under the condition that the lever is balanced in horizontal position and the directions of force and resistance are vertical downward, that is, the direction of force or resistance is not changed during the experiment. Therefore, options A, C and D are wrong and option B is correct.
So the answer is: (1) arm of force; (2)6; ? (3)B。