=[﹙y+z﹚2-x2][x2-﹙y-z﹚2]

=

(2).(3) I can't see clearly

(4) First simplify the original formula =-2b/a.

3a2+AB-2B2 = 0 equals sign divided by a2 to get 3+(B/A)-2 (B/A) 2 = 0.

B/A =- 1 or 3/2.

So the original formula =2 or -3.