One grid of (1) lever is L. According to the lever balance condition F 1L 1=F2L2, we can get:

2×0.5N×5L=F×2L，

The results show that the pulling force F=2×0.5N×5L2L=2.5N, which is the index of spring dynamometer.

(2)

When the spring dynamometer pulls the lever vertically upwards, the pulling arm is OB, and the spring dynamometer tilts the lever to the right, and the pulling arm is smaller than OB, so the pulling arm becomes smaller, the pulling force becomes larger, and the pointer of the spring dynamometer becomes larger.

So the answer is: 2.5; Get bigger.