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How to solve the application problem of unit 7 in the third grade math exam in primary school
The application questions in Unit 7 of the third grade math test in primary school are as follows:

A passenger ship left Chongqing on August 30th 1 1: 00 and arrived in Wuhan on September 30th 17: 00. Voyage from Chongqing to Wuhan 1354 km. How many kilometers does this passenger ship travel per hour except for six hours at the dock?

A: The time difference between August 30th 1 1: 00 and September 30th 17: 00 is 30 hours.

The algorithm of time difference is as follows:

24- 1 1= 13? (hours)

13+ 17=30 (hours)

30-6=24 hours

1354÷24=56 (km) (rounded off after decimal point).

A: The speed of this passenger ship is about 56 kilometers per hour.

Extended data:

The ratio of distance to time is called speed. High school definition: speed is equal to the ratio of displacement to the time taken for displacement to occur. Symbol: V Note: The Greek letter υ stands for another physical quantity "displacement" definition: V = s/t.

Speed is the distance traveled per unit time, which is generally expressed by V. Common units are: meter/second, kilometer/hour and kilometer/hour. Distance is the length of the particle trajectory. There is no direction, only size, generally expressed by s, and the units are: meter, kilometer, kilometer, etc.

The relationship between distance, speed and time: distance = speed× time, speed = distance ÷ time, time = distance ÷ speed.

Baidu encyclopedia _ speed