From the above observations, we give proof.
S(n)=|∫+∞ 1 (sinnx/x*x)|
Set 2 kpis.
s(n)& lt; =max{ 2kPi to 2k+ 1Pi under integer, sinnx/x 2-(area of the first peak)
Under integer, 2k+ 1Pi to 2k+2Pi, -sinnx/x 2-(the area of the first valley).
}
Under integer, 2kPi to 2k+ 1Pi, sinnx/x 2.
Under the integer symbol, 2k+ 1Pi to 2k+2Pi, -sinnx/x 2 make the same estimation.
Therefore s (n)->; 0, (n tends to infinity)
Note: The above observations can be proved by analytical means, but they are trivial and will not be typed.