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How to practice the tenth question on page 2 1 in the first grade of mathematics?
Let the ten digits of the original three digits be x.

Then the original number =2x+ 10x+ 100(x+7).

The new three digits =2× 100x+ 10x+x+7.

So [2x+10x+100 (x+7)] ×? =2× 100x+ 10x+x+7+33

So x=2.

So the original three digits are 4+20+900=924.

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