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Math problems in the sixth grade of primary school are urgently needed to be solved by experts.
Solution 1:

The remaining boys: girls = 16: 15.

Each serving: 3/( 16- 15)=3 (person)

The remaining boys: 3x 16=48 (person)

The remaining girls: 3x 15=45 (person)

Male: 48/( 1- 1/9)=54 (person)

Female student: 45+3=48 (person)

Solution 2:

The remaining boys are 16, so the original boys are16/(1-kloc-0//9) =18.

Each copy: (102-3)/(18+15) = 3 (person)

Original boy: 3x 18=54 (person)

Original female student: 102-54=48 (person)