Ideas:

1, consider "I": 5 digits times 4, and the number I”:5 digits, then "I" can only be 1 or more than 2,3, and the number is 6 digits. And because any number multiplied by 4 is even, then "I" can only take 2.

2. Considering "Xue": after I = 2, we know that the end of "Xue× 4" is 2, so "Xue" can be 3 or 8; Because the first "I×4" equals "learning" (without carry) or "i× 4"

3. Consider "person": Based on "I" = 2 and "Xue" = 8, it can be judged that "person" ×4 does not carry, so "person" can choose 0, 1 or 2; Because "Xue" ×4 = 32, and "number "×4 must be an even number, so" male "can only choose 1.

4. After considering "number": "person" equals 1, it is judged that the end of "number" ×4 is 8. Therefore, the number can be 2 or 7. Considering that "number" is thousands of digits and greater than "person" ×4, "number" is selected as 7.

5. Consider "love": love multiplied by 4 needs to be rounded to 3 to satisfy "man (1) × 4 = number (7)", then "love" has 7, 8 or 9 alternatives. After investigation, "love" is 9.

Conclusion: I = 2, student = 1, love = 9, number = 7, learning = 8; 2 1978×4=879 12