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There is a math problem in the third grade of primary school that stumbles me. ABCAB*A=DDDDDD, what is ABCD?
Simple ~!

A=3

B=7

C=0

D= 1

37037*3= 1 1 1 1 1 1

Solution: If a = 1, 2 is not valid, because it is too small, so the answer can only be 3, 4, 5, 6, 7, 8, 9! If it is 4, at least 160000 and at most 199996 should be excluded! If it is 5, the minimum is 250000 and the maximum is 299995. Rule out! If it is 6, the minimum is 360000 and the maximum is 4 19994. Rule out! If it is 7, the minimum is 490,000 and the maximum is 559,993. There may be 555,555. 555,555 divided by 7 = 79,365 is invalid. Rule out! If it is 8, the minimum is 640000 and the maximum is 7 19992. Here is the possible number of 666666, which is the same as 66666 divided by 8=83333.25. Rule out! If it is 9, the minimum is 8 10000 and the maximum is 89999 1. At this time, 888888 came again, 888888 divided by 9 = 98765333 ... ~ ~ ~

So if A=3, the minimum is 90000, the maximum is 1 19997, and there is1165438 in the middle.

Hoo ~ finally ~ ~ In fact, I can tell at a glance ~ ~ In order to make the answer authoritative ~ ~ Rory is a lot ~