T makes TN perpendicular to AB and crosses AB to n.
If AT divides ∠BCA equally, there will be ∠CAT=∠NAT? ,
At rt δ cat? And then what? RtδNAT includes ∠CAT=∠NAT, ∠ACT=∠ANT=90 degrees, and AT=AT.
So, rt δ cat? All equal? rtδNAT
So ∠NTA=∠CTA, CT = TN-①.
What is the delta delta sum? And then what? In δδATN, ∠DAM=∠TAN.
So, δ δ and? Similar to δδATN
So ∠ADM=∠ATN
And because ∠ADM=∠CDT (opposite to each other)
So ∠CDT=∠CTD, ∠CTD is an isosceles triangle CD = CT-②.
Simultaneous ① ②, CD = TM-③.
Because DE//AB, δδCDE is similar to δ TNB-④.
It is concluded from ③ and ④ that Δ Δ CDE is equal to Δ Δ TNB, then CE=TB.
That is CT+TE=TE+BE.
Therefore, CT=BE.
There are many letters and symbols in the process, not only in Chinese, so it takes a long time to input, but nevertheless, I am willing to help you input the process to solve this problem. I hope what I input can help you!