According to the meaning of the question, f(x)=lnx-x+2=0?

De: lnx=x-2

Let y 1=lnx and y2=x-2.

According to the position relation of the images of these two functions in the same coordinate system:

Two images have two common * * * points, that is, y 1=y2 of these two points, so y 1-y2=0, that is:

lnx-(x-2)=0

The number of zeros is 2.