There are three more people in the fourth row (4-3= 1, also 1), and the number of boys may be 71,15, 19, 23, 27, 3/kloc-.
The minimum number that the two are equal is11;
The formula is 3×4= 12,12-1=1(person).
There are 1 girls in the five elements, and the number of girls may be 9 14, 19, 24, 29, 34, 39, etc.
There are five more people in the sixth row (6-5= 1, also 1), and the number of girls may be 1 1 7, 23, 29, 35, 4 1 and so on.
The minimum number that the two are equal is 29;
The least common multiple of 5 and 6 is 5× 6 = 30,30-1= 29 (person).
Therefore, the minimum number of physical education class students in 1 class is 1 1+29=40 (people).
Solution: 3× 4 = 12 (person)
12-1=11(person)
5 * 6 = 30 (person)
There are/kloc-0 boys in the third row, and the number of boys may be 5, 8, 11,14, 17, 20, 23, 26, 29, 32, 35, etc.
There are three more people in the fourth row (4-3= 1, also 1), and the number of boys may be 71,15, 19, 23, 27, 3/kloc-.
The minimum number that the two are equal is11;
The formula is 3×4= 12,12-1=1(person).
There are 1 girls in the five elements, and the number of girls may be 9 14, 19, 24, 29, 34, 39, etc.
There are five more people in the sixth row (6-5= 1, also 1), and the number of girls may be 1 1 7, 23, 29, 35, 4 1 and so on.
The minimum number that the two are equal is 29;
The least common multiple of 5 and 6 is 5× 6 = 30,30-1= 29 (person).
Therefore, the minimum number of physical education class students in 1 class is 1 1+29=40 (people).
Solution: 3× 4 = 12 (person)
12-1=11(person)
5 * 6 = 30 (person)
30- 1 = 29 (person)
1 1+29 = 40 (person)
Answer: 1 class has at least 40 students from physical education class. 30- 1 = 29 (person)
1 1+29 = 40 (person)
Answer: 1 class has at least 40 students from physical education class.