(x- 1)(x- radical number 3)=0

Two solutions 1 and root number 3 satisfying the conditions are obtained.

The second equation, the decomposition factor

(mx+ 1)(x- 1)=0

The solutions are x=- 1/m and x= 1.

It can be known that m < 0

Then-1/m > 1 and-1/m < 2.

The solutions are m >- 1 and m.

So- 1 < m