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The first volume of the eighth grade mathematics textbook of Beijing Normal University
B leaves at 2 o'clock before A, so they meet after A 3. How many kilometers did A and B walk each time?

Change the above conditions! B leaves 2 hours before A, not 2 hours before A can solve it!

Solution:

Let the speed be x kilometers and the speed of b be y kilometers.

4.5x+2.5y=36

3x+5y=36

According to the above two formulas, x=5/3y is obtained, and this formula is brought into 3x+5y=36.

Get y=3.6, and bring y=3.6 into x=5/3y to get x=6.

So the speed of A equals 6 kilometers, and the speed of B equals 3.6 kilometers.