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The problem of filling in the blanks with univariate function in junior two mathematics is urgent.
Solution: 4. The intersection of the function image and the Y axis is (0, -2).

∴x=0,y=-2

That is -k+4=-2.

k=6

The expression is y=6x-2.

8.∫ Function image passing point (1, 3)

∴x= 1,y=3

That is m-4m+4=3.

m= 1/3

The analytical formula is y= 1/3x.

In this case, the function is a proportional function.

Hope to adopt! ! !