Solution: 1) is equipped with X tons of goods, so Party A transports x/2a tons and Party B transports x/a tons of goods, so the freight volume of Party B is twice that of Party A..

2) Party C transports m tons of goods at a time. Then Party A and Party C shipped 360a/x times, Party C shipped 360m/x tons, Party B and Party C shipped 240a/x times, and Party C shipped 240m/x tons.

So 360 am/x+180 = 240 am/x+240 = m.

So am/x= 1/2 m=360.

It is also known that when the merger times of Party A and Party C are the same, Party A * * * transports 180 tons, that is, the quantity of goods transported by Party A and Party C is the same, which is Party B's 1/2, and the total freight is 20 * 360 = 7200. Therefore, the number of mergers between Party A and Party C is the same, and Party A and Party C each get 65,438.