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Mathematical problem presentation
(2) There should be three models of X, Y and Z vehicles: A, B and C..

5x+8y+ 10z= 120……①,

x+y+z= 14……②

②* 10-① to obtain

5x+2y=20,

y=(20-5x)/2,

According to the meaning of the question, x, y and z are all natural numbers.

5x must be an even number less than 20,

X can only take 2.

When x=2 and y=5,

Substitute ② to get z=7.

400*2+500*5+600*7=7500 yuan.

The quantities of the three models are 2, 5 and 7 respectively, and the freight at this time is 7500 yuan.