Here is a math problem. Who can help? If you buy Ax, By and Cz, then

x+y+z=36

6000x+4000y+2500z= 100500

The first formula is multiplied by 2500 on both sides, and then subtracted from the second formula.

3500x+ 1500y= 10500

x =( 10500- 1500y)/3500

x=(2 1-3y)/7

Because the values of x, y and z are integers, y can only take the value of 0 or 7, and then calculate x and z respectively:

x=3 y=0 z=33

x=0 y=7 z=29

So there are two choices, that is, buy A3, B don't buy it, C33 don't buy it, B7, C29.

Solution 2

X-type platform

x+y=36

6000x+4000y= 100500

X=-2 1.75, which is impossible.

X-type platform, c-type platform

x+y=36

6000x+2500y= 100500

The solution is x=3 and y=33.

Type b x platform, type c y platform

x+y=36

4000x+2500y= 100500

The solution is x=7 and y=29.

Two schemes: 3 units of type A and 33 units of type C; B-type 7, C-type 29.

A math problem ~ which master will help! ! The answer is wrong.

How did it happen 0.5 times?

The long one should be sawed into 4 sections, one section should be sawed 3 times, and the short one should be sawed into 2 sections, and sawed 1 time.

Long log 10, short log 5.

So 3* 10+ 1*5=35 times.

A math problem, which expert can help ~ ~ Turn x 2cosa-y 2sina+2 = 0 into a standard form, and make the equal sign 1 on the right.

Now it's easy to see that to make it an ellipse, COSA

So the circle (x+COSA) 2+(y+Sina) 2 = 1 is in the fourth quadrant.

A math problem, please help (1)A27+A36+A64+A73.

=4×A 1+ 196d

=2×(A 1+98d)+2A 1

=2×A99+2A 1

=224;

(2)A3+A7=2A 1+8d=-2……①

a4×a6=a 1^2+8a 1×d+ 15d^2=- 15……②

You can get A 1=-5, d= 1, and then you can do it ~

A math problem, master help! (1) proof: because EG∨AF

So angel ·EGB = angel ·ACB

Because AB=AC

So angle B= angle ACB

So angle B= angle EGB.

So GE=BE

(2) because BE=CF and GE=BE.

So EG=CF

And because eg Σ af

Angle GED= angle CFD

Because angle EDG= angle FDC.

So the triangle EGD is equal to the triangle FCD.

So ED=DF

Which expert can help solve a math problem? Solution: C.

It is easy to know that a four-layer hollow square matrix has X potted flowers on each side of the outermost layer.

There are (x+8) potted flowers on each side of the outermost layer of a two-layer hollow square.

The total number of flowers in a 4-level square matrix is

x ^ 2-(x-8)2 = 16x-64。 (where x 2 represents the square of x)

The total number of flowers in a 2-level square matrix is

(x+8)^2-(x+8-4)^2=8x+48.

Judging from the meaning of the question.

16x-64=8x+48

16x-8x=64+48

8x= 1 12

x= 14

So the total number of flowerpots is

x^2-(x-8)^2

= 14^2-6^2

= 160

Here is a math problem. Help! 15× (180-1) = 2685 (m)

A: I ran 2685 meters.

Urgent ... Who can help me? A math problem in grade one, the same as △ABC and △ADE.

Proof: ∠ 1=∠2, ∠ BAC = ∠1+∠ DAC = ∠ 2+∠ DAC = ∠ DAE,

∵∠2=∠3,∠DFC=∠AFE,∴∠C=∠E，

Ab = ad, ∴△ABC and △ADE congruences (A.A.S)

A math problem. Help! Masters. Solution:

1.a？ +b？ =(a+b)？ -2ab=a？ +2ab+b？ -2ab=2？ -2× 1=2

(a-b)? =a？ -2ab+b？ =2-2ab=2-2× 1=0

2.a+ 1/a=3

(a+ 1/a)？ =9

Answer? +2×a× 1/a+ 1/a？ =9

Answer? + 1/a？ +2=9

Answer? + 1/a？ =7

A math problem, please help solve it. 1/3+2/3= 1

1/4+2/4+3/4=2/4+ 1= 1/2+ 1

1/5+2/5+3/5+4/5=( 1/5+4/5)+(2/5+3/5)= 1+ 1

1/6+2/6+3/6+4/6+5/6=( 1/6+5/6)+(2/6+4/6)+3/6= 1+ 1+ 1/2

You should be able to see the pattern.

Then the denominator of 7 is 1+ 1+ 1.

The result of 8 as the denominator is1+1+1+1/2.

9 is1+1+1+1.

For 10, it is1+1+1+/2.

So the original formula = 1/2+2/2+3/2+...+59/2.

=( 1+2+……+59)/2

=59*60/2/2

=885