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About the math problem of the second day of junior high school (Chapter 14: Calculation of linear function and triangle area), urgent, urgent, urgent! ! ! ! ! thank you
Because that intersection of the linear function and the y axis is a,

therefore

The coordinates of point A are (0, -3).

Because two straight lines intersect at point c,

So point c is on the image of linear function y=2x-3,

Because the ordinate of point C is 1,

Therefore, the ordinate 1 of point C is brought into the linear function y=2x-3, and the coordinate of point C is (2, 1).

Delta area Delta △= AB * C = AB * C abscissa of AB * C ÷2

So AB= 16

So there are two situations: ① point B is above the X axis and ② point B is below the X axis.

Because the coordinates of point A are (0, -3).

Therefore, when B is above the X axis, the coordinate of point B is (0, 13).

At this time, let the analytical formula of another straight line be y=kx+b, and the analytical formula of the straight line with points b and c as coordinates be y=-6x+ 13.

② When B is below the X axis, the coordinate of point B is (0,-19).

At this time, the analytical formula of another straight line is also set to y=kx+b, and the analytical formula of the straight line brought into the coordinates of point B and point C is y= 10x- 16.