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In the Encyclopedia of Mathematics Additional Questions in Grade One, 1, 12, 13, 14, 15, 16, 17, 18.
How to calculate1121314151718/kloc-0.

2+8= 10

... and so on, and finally,

4 10+ 10+5 = 40+ 10+5 = 55.

214161810 ...168 Solving the fourth grade math problem with simple calculation 21416/kloc-0.

2 14 16 18 1 10 ... 168

=(2+68)+(4+64)+ ....

=70* 17

= 1 190

2+4+6+8+ 10+……+68

=(2+68)×[(68-2)÷2+ 1]÷2

=70×34÷2

= 1 190

1121314151617+819 * o Jill1+2.

214161810 …1961981oo arithmetic progression.

2+4+6+8+ 10.+96+98+ 100

=(2+ 100)x50/2(/ is a divisor)

= 102x50/2

=5 100/2

=2550

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112-3141516-718 ...10 201kloc-0. So the result is the result of multiplying each group by the number of groups.

(11214) ten (5 16 17 18) ten ... ten (20 13)

)

=(-4)*(20 16/4)

=-20 16

1 12 13 14 15 16 17 18 19 16 5438+00 2? Answer 55 A Qiang

Q 1 10 1 135,678,928 =? 1 10 1 135,678,928

=( 1+9)+(3+7)+(2+8)+( 1+6+8+5)

= 10+ 10+ 10+20

=50

(241610.10 2016)10 (1350-10 20/kloc)

= 1x20 16/2

= 1008