BE = CF because AB=AC and AE=AF (radius of the same circle) are known.
∠B=∠C
So △ bed △ CFD
So DE=DF
2. Because BC=8, BD = DC = 4;; AD = AE = AF = 3; According to Pythagorean Theorem, AB=AC=5.
Because ∠A is public, AE=AF, AB=AC, so △AEF∽△ABC, so AE: AB = EF: BC.
That is, 3: 5 = ef: 8, and EF=*