Deduction of gravity: If the orbit of the planet is approximately regarded as a circle, the angular velocity of planetary motion can be obtained from Kepler's second law, namely:
Ω = 2π/t (period)
If the mass of the planet is m, the distance from the sun is r and the period is t, then from the equation of motion, the force acting on the planet is
mrω? =mr(4π? )/T?
In addition, it can be obtained from Kepler's third law
t? /r cubic; = constant k'
So the force in the direction of the sun is
mr(4π? )/T & amp; ? ; = MK’(4π? ; )/r? ;