A math problem in grade one. thank you

Solution: (1) If each schoolbag buys X yuan, then each dictionary is (X-36) yuan, and the equation can be listed:

3x+4(x-36)=248

7x- 144=248

7x=392

Solution:

x=56

So every schoolbag 56 yuan, every dictionary 20 yuan.

(2) If there are 40 people in the class with Y schoolbags, then the dictionaries of (40-y) people can be classified as an unequal group:

1500-360≤56y+20(40-y)≤ 1500-250

1 140≤36y+800≤ 1250

340≤36y≤450

85/9≤y≤25/2

Because y is an integer, the values of y are 10, 1 1, 12.

So * * * there are three schemes:

Buy 10 schoolbag and 30 dictionaries;

Purchase 1 1 schoolbag and 29 dictionaries;

Buy 12 schoolbag and 28 dictionaries.