Because the speed of sound propagation in air y (m/s) (sound speed for short) is a linear function of air temperature x(℃).

So let y = kx+b.

Substitute (0,331) and (5,334) into y = kx+b.

b=33 1

{

5k+b=334

The solution is k=3/5.

{

b=33 1

So y=3/5x+33 1.

(2) Solution:

When the temperature x=22(℃), the speed y = 3/5 * 22+33 1 = 344.2 (m/s).

So the distance between this person and the place where fireworks are set off is about 344.2 * 5 = 172 1 (m).

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