However, if we can connect some simple knowledge of mathematics and physics, we can work out the answer to this question through the knowledge of elementary mathematics and physics. Here is a brief introduction to the idea:
1. Elliptic orbit is symmetrical along the long axis, which can be proved if high school mathematics has not forgotten.
2. Kepler's second law: the connecting line between the satellite and the central celestial body sweeps the same area in unit time.
With the first point, we know that the area of elliptical orbit is divided into two along the semi-long axis; With the second point, we know that the running time from point B to point A is half of the period around the elliptical orbit AB.
The next step is to use Kepler's third law, and the square of the period of celestial motion is directly proportional to the cube of the half-length diameter of the orbit. What is the half-length diameter of ellipse AB? (R+r)/2, and the required period is set to x:
Then it is: x 2/[(r+r)/2] 3 = t 2/r 3.
Speaking of which, you can know the answer just by verbal calculation, right? Please help yourself with the specific values.