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How to do applied mathematics in junior college? Questions 3, 4 and 7 give the calculation process.
Solution (Question 3): ∫ [(x+1) 72 (2x-1) 28]/(3x-4)100 = [(x+1)/(3x-4).

Solution (Question 4): √√ (N2+N)-N = n/[√ (N2+N)+N] =1[√ (1+N)+65438+.

Solution (Question 7):∫x→∞, f (x) = ax+(b-a-1)+c/(1+x 2), where c is a constant, if a≠0, b-a-652. ∴a=0,b= 1。 For reference.