1) let x >；; = 1, a>= 1, ax comes from the solution set; = 1, so a has no solution at this time;

Let x>= 1, a<= 1, ax.

Let x < 1, a>= 1, ax>x-1x > 1/( 1-a) a= 1/2 is obtained from the solution set, and A has no solution at this time;

Let x < 1, a<= 1, ax>x-1x < 1/( 1-a) a=0 from the solution set;

And because there is no solution when a=0, a= 1/2.

2) when 4(a-2) squared-16(a-2) >; At 0, the inequality holds for all x∈R, that is, Party A-8a+12 >; 0, a belongs to {a | a}