∴√3(ccosA+acosC)=2bcosA,
∴√3b=2bcosA,
∴cosA=√3/2,A=π/6.
2.B=π/6=A,
∴b=a,C=2π/3,
According to the cosine theorem, the median line of BC is AM = √ [A2+(A/2) 2+A2/2] = (√ 7/2) A = √ 7,
∴a=2,
∴S△ABC=( 1/2)a^2*sinC=√3.