1. Original formula = 587 ÷ 58.7× 2.68 ÷ 26.8×19×1.9.

= 10×0. 1×36. 1=36. 1

2.27 = 0.2 857 1.4, so 0.2 85.

The circumference is 500+300 ×2= 1600 meters.

So we need to increase 1600÷2? 1600÷2.5= 160 pots

There are 1 potted flowers per 10 meter, and a total of * *1600 ÷10 =160 pots need not be moved.

4. The grasshopper jumped 1+2+3+? +100=5050 steps

5050 ÷ 6 = 84 1 ...4, so at this time, the grasshopper is equivalent to jumping 4 steps and reaching position 5.

5. 147? 144 ÷ 149? 147 = 1.5 (times)

6. Draw a line diagram and see that the original number of trucks is 3.5? 2.3= 1.2 times, which is exactly 2.3 times of 6 plus 3.

So the original car is 6×2.3+3 ÷ 3.5? 2.3 = 14 vehicles, while the original * * stopped 14× 1+3.5 =63 vehicles.

7.0. Every/kloc-0 stamp from 5 yuan corresponds to four stamps from 0.8 yuan, which is equivalent to 0.5+0.8× 4 =/kloc-0 stamp from 3.7 yuan.

Suppose there are x stamps in 3.7 yuan and y stamps in 1.2 yuan, and the indefinite equation is 3.7x+ 1.2y=60.

That is, 37x+ 12y=600, and x must be a multiple of 12 and only 12, so y= 13.

8. If you don't carry, the parity of each bit will become the opposite after adding 1, so the desired number plus 1 must be the unwanted number, and the unwanted number plus 1 must be the desired number.

Therefore, in a continuous group of 10 numbers with bits from 0 to 9, there must be 5 expected numbers and 5 unexpected numbers. Although 0 is not a natural number, 1 group is also five hope numbers from 1 to 9. 20 10÷5=402, so the hope number 20 10 happens to be the last hope number in the 402nd group, that is, 40 19.

9. Let the distance between AB be X, AC be Y and BC be Z, and x+z= 10, z+y= 13, y+x= 1 1.

Add up the three formulas and divide by 2 to get x+y+z= 17, so the distance between the two scenic spots with the shortest distance is 17? 13 = 4km.

10. Let the length, width and height of a cuboid be A, B and H, respectively, and get that b×h=48÷2=24, a×h=99÷3=33, a×b=352÷4=88, so the surface area is 24.

11.16+24 =40, so up+left+front+up+right+back = 40.

And the sum of the points on each opposite side is 13, so up+left+front+down+right+back = 13×3=39.

Comparable? Down = 1. Up+down = 13, then down = 13? 1 ÷2=6。

12. Note that 6 times the divisor is 3 digits, and 100 divided by the divisor is less than 7, so the divisor can only be 15 or 16.

If it is 15, 6 times 15 equals 90, and the three-digit minus 90 cannot be less than 10.

So the divisor is 16 and the quotient is 6.65.

13.( 1) No, please note that the center number cannot be filled after the first line is filled in.

(2) Yes. As shown on the right

14. It takes 360÷ 40+80 =3 hours for the first encounter, and it still takes 3 hours for the motorcycle to return;

Did you get 360 for the second meeting? 40×6 ÷ 40+80 = 1 hour, motorcycle return needs 1 hour;

It took (360? 40×8)÷(40+80)= 13 hours, and it takes 13 hours for the motorcycle to return.

Up to now, all six cases of medicine have been shipped, which took eight 23 hours and the motorcycle traveled 823 ×80=693 13 kilometers.

15. The area of triangle AFD is 6 and the area of DFE is 4, so the length ratio of AF and EF is 3 to 2.

The area of triangle BEF is equal to the area of AFD, which is equal to 6. So the area of triangle ABF is 6÷2×3=9.

The area of triangle ABD is 6+9= 15, then the area of triangle BCD is 15, and the area of quadrilateral BCEF is 15? 4= 1 1。

16. There are four arrangements of the T-shaped frame. According to the situation, only 1 can satisfy the meaning of the question, with the minimum number of 15 and the maximum number of 30.