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Fractional operation of math problems in grade one of junior high school.
2/[X-2]+MX/[X^2-4]=3/[X+2]

The comprehensive score after denominator removal: 2(X+2)+MX=3(X-2).

2X+4+MX=3X-6

(M- 1)X=- 10

pass by

2/[x -2]+MX/[x 2-4] = 3/[x+2] It is known that when X=2 or -2, the equation has an increasing root.

Substituting X=2 into (M- 1)X=- 10, it is obtained.

2(M- 1)=- 10

2M-2=- 10

M=-4

Substitute X=-2 into (M- 1)X=- 10 to obtain

-2(M- 1)=- 10

-2M+2=- 10

M=6

Therefore, when M=-4 or 6, the equation 2/[x-2]+MX/[x 2-4] = 3/[x+2] about x will produce root growth.