Excuse me, have CG and AD been given to T?
∠D+∠G=∠MTA
∠A+∠MTA=∠TME
Let CF and BE meet in H.
∠TME+∠E=∠HTC
Similarly ∠ CHT = ∠ B+∠ F.
∠E+∠A+∠D+∠G =∠HTC = 180-(∠TCH+∠CHT)= 180-(∠C+∠b+∠F)
= 180-( 14+ 15+ 16)= 180-45 = 135 = k * 45
k=3