Excuse me, have CG and AD been given to T?

∠D+∠G=∠MTA

∠A+∠MTA=∠TME

Let CF and BE meet in H.

∠TME+∠E=∠HTC

Similarly ∠ CHT = ∠ B+∠ F.

∠E+∠A+∠D+∠G =∠HTC = 180-(∠TCH+∠CHT)= 180-(∠C+∠b+∠F)

= 180-( 14+ 15+ 16)= 180-45 = 135 = k * 45

k=3