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Concrete mix proportion problem
This should be regarded as a mathematical problem. My calculation is 1:2.23:4. 17:0.52 (sand ratio is constant, aggregate quantity is reduced).

Sand ratio is 2.36/(4.43+2.36)= 0.347.

The original mixing ratio of water and ash is 1+0.52= 1.52.

The new water-ash mixing ratio is1.52 *1.05 =1.596.

The aggregate of the new mixture ratio is (1+2.36+4.43+0.52)-1.596 = 6.714.

The total amount of fine aggregate in the new mixture ratio is 6.7 14*0.347 = 2.33.

The total amount of coarse aggregate is 6.7 14-2.33 = 4.38.

The new mixing ratio is1.05: 2.33: 4.38: (0.52 *1.05) =1:2.23: 4.17: 0.52.