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Junior high school mathematics for two years
Method one

Solution: 176000÷2=88000 (yuan)

88000-80000=8000 (yuan)

8000÷4=2000 (pieces) ... The number of pieces purchased for the first time.

2000×2=4000 (pieces) ... Number of pieces purchased for the second time.

(2000+4000-150) × 58 = 339300 (yuan)

150×58×0.8=6960 (yuan)

339300+6960-80000-176000 = 90260 (yuan)

The profit is 90260 yuan.

Method 2

Solution: If the purchase price of the first fashion is X, then purchase 80,000/x pieces.

Then the purchase price of the second fashion is x+4, and the purchase price is 176000/(x+4) pieces.

And because the number of pieces purchased for the second time is twice that of the first time,

Then 2×80000/x= 176000/(x+4),

160000 *(x+4)= 176000 * x,

16000x=640000,

Then x=40.

Then the store * * * buys clothes: 80000/40+(80000/40) * 2 = 2000+4000 = 6000 (pieces).

If you have to calculate the sales price twice, is it profitable? The answer is as follows:

Then the first sales amount is: 58× 80000/40 =116000 (yuan),

The second sales amount is: 58× [176000/(40+4)-150]+150× 58× 80% = 230260 (yuan).

Then116000+230260-80000-176000 = 90260 > 0,

That is to say, the store is profitable in this business, with a profit of 90260 yuan.